Question
In which oxidation state, is vanadium diamagnetic?
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Answer
The electronic configuration of vanadium is, $_{23}V [Ar] 3d^3 4s^2.$
In $+5$ oxidation state, the electronic configuration is, $V ^{5+}[ Ar ]$..
Since in $V^{5+}$ state, vanadium has all electrons paired, it is diamagnetic.
In $+5$ oxidation state, the electronic configuration is, $V ^{5+}[ Ar ]$..
Since in $V^{5+}$ state, vanadium has all electrons paired, it is diamagnetic.
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