MCQ
In $Xe{F_2}$ hybridisation of $Xe$ is
  • A
    $s{p^2}$
  • $s{p^3}d$
  • C
    $s{p^3}$
  • D
    $s{p^3}{d^2}$

Answer

Correct option: B.
$s{p^3}d$
b
$Xe$ has $3$ lone pairs and it forms $2 Xe - F$ bonds.

Hybridisation of a atom with $3$ lone pairs and $2$ bond pairs is $sp ^3 d ^2$.

So, the hybridisation of $Xe$ is $sp ^3 d$.

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