MCQ
In $Xe{F_2}$ hybridisation of $Xe$ is
- A$s{p^2}$
- ✓$s{p^3}d$
- C$s{p^3}$
- D$s{p^3}{d^2}$
✓
Answer
Correct option: B.
$s{p^3}d$
b
$Xe$ has $3$ lone pairs and it forms $2 Xe - F$ bonds.
$Xe$ has $3$ lone pairs and it forms $2 Xe - F$ bonds.
Hybridisation of a atom with $3$ lone pairs and $2$ bond pairs is $sp ^3 d ^2$.
So, the hybridisation of $Xe$ is $sp ^3 d$.
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