MCQ
In $Xe{F_4}$ hybridization is
- ✓$s{p^3}{d^2}$
- B$s{p^3}$
- C$s{p^3}d$
- D$s{p^2}d$
✓
Answer
Correct option: A.
$s{p^3}{d^2}$
(a) $Xe{F_4}$ has $s{p^3}{d^2}$ hybridisation, its shape is square planar.
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