MCQ
In $YDSE$ experiment, when two light rays make third minima, then they have
- APhase difference of $3\pi $
- BPhase difference of $\frac {5\pi }{2}$
- CPath difference of $3\lambda $
- ✓Phase difference of $\frac {5\lambda }{2}$
✓
Answer
Correct option: D.
Phase difference of $\frac {5\lambda }{2}$
d
For minima, path difference $\Delta=(2 n-1) \frac{\lambda}{2}$
For minima, path difference $\Delta=(2 n-1) \frac{\lambda}{2}$
For third minima $n=3 \Rightarrow \Delta=(2 \times 3-1) \frac{\lambda}{2}=\frac{5 \lambda}{2}$
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