In Young's double slit experiment, in an interference pattern sec… - Vidyadip

MCQ

In Young's double slit experiment, in an interference pattern second minimum is observed exactly in front of one slit. The distance between the two coherent sources is $d$ and the distance between source and screen is $D$. The wavelength of light source used is

A
$\frac{d^2}{D}$
B
$\frac{d^2}{2 D}$
✓
$\frac{d^2}{3 D}$
D
$\frac{d^2}{4 D}$

✓

Answer

Correct option: C.

$\frac{d^2}{3 D}$

(c) : The position of minimum is
$
x=\frac{(2 n-1)}{2} \frac{D \lambda}{d}
$
or $\frac{d}{2}=\left(\frac{2 \times 2-1}{2}\right) \frac{D \lambda}{d}$
$
(\because n=2)
$
$
\frac{d}{2}=\frac{3}{2} \frac{D \lambda}{d} \text { or } \lambda=\frac{d^2}{3 D}
$

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