MCQ
In Young's double slit experiment, the two slits are ' $d$ ' distance apart. Interference pattern is observed on the screen at a distance ' $D$ ' from the slits. First dark fringe is observed on the screen directly opposite to one of the slits. The wavelength of the light is
  • $\frac{d^2}{D}$
  • B
    $\frac{D^2}{d}$
  • C
    $\frac{d^2}{2 D}$
  • D
    $\frac{D^2}{2 d}$

Answer

Correct option: A.
$\frac{d^2}{D}$
(a) : For $n^{\text {th }}$ dark fringe, $(2 n-1) \frac{\lambda D}{2 d}=\frac{d}{2}$
$
\lambda=\frac{d^2}{(2 n-1) D}=\frac{d^2}{D}
$(For $n=1$)

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