Question
In Young's interference experiment, if the slits are of unequal width, then:

Answer

  1. The positions of minimum intensity will not be completely dark.
Explanation:
Unequal width of slits will cause unequal intensity of lights entering from both slits.
As a result, during interference complete cancelling of light intensity will not take place at regions of otherwise dark fringe.
As the value of $\beta$ does not depend on intensity of light, there will be no shifting of fringes as well as no change in fringe width.

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