MCQ
Incorrect match is
- A$2-$ Bromobut $-3-$ ene
- B$1-$ methoxyprop $-2-$ ene
- C$\begin{array}{*{20}{c}}
{\,\,\,\,C{H_3}} \\
{|\,} \\
{C{H_3} - C - OH} \\
{\,|\,\,} \\
{\,\,\,\,C{H_3}}
\end{array}$ $1,1-$ Dimethylethanol - ✓All
✓
Answer
Correct option: D.
All
d
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The correct match between Item$-I$ (starting material) and Item$-II$ (reagent) for the preparation of benzaldehyde is :
→Item$-I$ Item$-II$
$(I)$ Benzene $( P )$ $HCl$ and $SnCl _{2}, H _{3} O ^{+}$
$(II)$ Benzonitrile $(Q)$ $H _{2}, Pd - BaSO _{4}, S$ and quinoline
$(III)$ Benzoyl Chloride $(R)$ $CO , HCl$ and $AlCl _{3}$
Correct configuration of following compound is :-
When chloroform is treated with excess oxygen it forms
Benzene and naphthalene form an ideal solution at room temperature. For this process, the true statement$(s)$ is (are)
→$(A)$ $\Delta G$ is positive $(B)$ $\Delta S _{\text {system }}$ is positive
$(C)$ $\Delta S _{\text {surroundings }}=0$ $(D)$ $\Delta H =0$
The total energy of the electron of $H-$ atom in the second quantum state is $-E_2$. The total energy of the $He^+$ atom in the third quantum state is
→| Column $I$ | Column $II$ | ||
| $(A)$ | Kohlrausch law can calculate | $(P)$ | $\frac{{\Lambda _m^c}}{{\Lambda _m^o}}$ |
| $(B)$ | Molar conductance ${\Lambda _m}$ | $(Q)$ | $\frac{1}{R} \times \frac{l}{A}$ |
| $(C)$ | Specific conductance Kappa $\to (k)$ | $(R)$ | $\Lambda _m^o\,of\,c{a_3}{(P{O_4})_2}$ |
| $(D)$ | Degree of ionization of weak electrolyte | $(S)$ | $\frac{{k \times 1000}}{M}$ |
Which of the following option show correct matches
Which solution of $NaNO_3$ will have maximum specific conductance ............ $\mathrm{N}$
→The ratio between the neutrons in $C$ and $Si$ with respect to atomic masses $12$ and $ 28$ is
→The correct order of the following complexes in terms of their crystal field stabilization energies is :
Major product of following reaction will be
