MCQ
Increasing order of acidic character would be
- A$C{H_3}COOH < {H_2}S{O_4} < {H_2}C{O_3}$
- B$C{H_3}COOH < {H_2}C{O_3} < {H_2}S{O_4}$
- ✓${H_2}C{O_3} < C{H_3}COOH < {H_2}S{O_4}$
- D${H_2}S{O_4} < {H_2}C{O_3} < C{H_3}COOH$
✓
Answer
Correct option: C.
${H_2}C{O_3} < C{H_3}COOH < {H_2}S{O_4}$
(c) Decreasing order of acidic character is ${H_2}S{O_4} > C{H_3}COOH > {H_2}C{O_3}$
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