MCQ
Increasing order of electron affinity is
- A$N < O < Cl < Al$
- B$O < N < Al < Cl$
- ✓$Al < N < O < Cl$
- D$Cl < N < O < Al$
✓
Answer
Correct option: C.
$Al < N < O < Cl$
c
Let us arrange the elements according to the way they are arranged in the periodic table.
Let us arrange the elements according to the way they are arranged in the periodic table.
Lithium ,Beryllium ,Boron ,Carbon ,Nitrogen ,Oxygen, Fluorine, Aluminium Chlorine
As we move from Lithium to fluorine the electron affinity increases and as we move from Fluorine to chlorine and further electron affinity decreases. Hence electron affinity of chlorine should be greater than oxygen and oxygen should be greater than nitrogen and nitrogen should be greater than aluminium. As we move down, the size increases, and due to that, the electron affinity decreases as it is the tendency to gain electrons. Metals do not gain electrons, nonmetals do. So, aluminum is at the last position.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In above reaction identify major product $(A)$ of the reaction
→The element $X, Y, Z$ and $T$ have the indicated electronic configurations. Starting with the innermost shell, which is the most metallic element
→Hydrolysis of an ester gives a carboxylic acid which on Kolbe’s electrolysis yields ethane. The ester is
The electronic configuration of Einsteinium is : (Given atomic number of Einsteinium = 99)
Nitration of aniline also gives $m-$nitro aniline, in strong acidic medium because
→In the above conversion of compound $( X )$ to product $(Y)$, the sequence of reagents to be used will be:
→$18\, g$ glucose $(C_6H_{12}O_6)$ is added to $178.2\, g$ water. The Vapour pressure of pure water at $100\,{\,^o}C$ (in $torr$) for this aqueous solution is :
→$(i)\,\,\begin{matrix}
CHO\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
{{(CH-OH)}_{3}}\,\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\,\,C{{H}_{2}}-OH\,\,\,\,\,\,\,\,\,\, \\
\end{matrix}\xrightarrow{4HI{{O}_{4}}} Product$ $(ii)\,\,\begin{matrix}
C{{H}_{2}}OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
{{(CH-OH)}_{4}}\,\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\,\,C{{H}_{2}}-OH\,\,\,\,\,\,\,\,\,\, \\
\end{matrix}\xrightarrow{5HI{{O}_{4}}} Product$
→CHO\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
{{(CH-OH)}_{3}}\,\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\,\,C{{H}_{2}}-OH\,\,\,\,\,\,\,\,\,\, \\
\end{matrix}\xrightarrow{4HI{{O}_{4}}} Product$ $(ii)\,\,\begin{matrix}
C{{H}_{2}}OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
{{(CH-OH)}_{4}}\,\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\,\,C{{H}_{2}}-OH\,\,\,\,\,\,\,\,\,\, \\
\end{matrix}\xrightarrow{5HI{{O}_{4}}} Product$
Ratio of moles of formic acid obtained in reaction $(i)$ and reaction $(ii)$ is
The diazonium salts are the reaction products in presence of excess of mineral acid with nitrous acid and
A coordination complex of type $MX_2Y_2$ ($M-$ metal ion; $X , Y-$ monodentate ligands), can have either a tetrahedral or a square planar geometry. The maximum number of possible isomers in these two cases are respectively
→