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| Rainfall (mm) | Number of sub-divisions (f) | Cumulative frequency |
| 200-400 | 2 | 2 |
| 400-600 | 4 | 6 |
| 600-800 | 7 | 13 |
| 800-1000 | 4 | 17 |
| 1000-1200 | 2 | 19 |
| 1200-1400 | 3 | 22 |
| 1400-1600 | 1 | 23 |
| 1600-1800 | 1 | 24 |
| N = 24 |
We have, $N=\Sigma f_i=24 \Rightarrow \frac{N}{2}=12$
The cumulative frequency just greater than $\frac{N}{2}$ i.e. 12 is 13 and the corresponding class is 600-800. It is the median class with l = 600 f = 7 h = 200 and F = 6.
$\therefore \quad$ Median $=l+\frac{\frac{N}{2}-F}{f} \times h \Rightarrow$ Median $=600+\frac{12-6}{7} \times 200=600+171.4=771.4 mm$
(iii)
Computation of Mean
| Rainfall (mm) | Mid values $\left(x_i\right)$ | $\frac{x_i-1100}{200}=u_i$ | Number of Sub-divisions $\left(f_i\right)$ | $f_i u_i$ |
| 200-400 | 300 | -4 | 2 | -8 |
| 400-600 | 500 | -3 | 4 | -12 |
| 600-800 | 700 | -2 | 7 | -14 |
| 800-1000 | 900 | -1 | 4 | -4 |
| 1000-1200 | 1100 | 0 | 2 | 0 |
| 1200-1400 | 1300 | 1 | 3 | 3 |
| 1400-1600 | 1500 | 2 | 1 | 2 |
| 1600-1800 | 1700 | 3 | 1 | 3 |
| $\Sigma f_i u_i=-30$ |
We find that a = 1100 200, N = 24
Mean $=a+h \times\left(\frac{1}{N} \Sigma f_i u_i\right) \Rightarrow$ Mean $=1100+200 \times \frac{-30}{24}=1100-250=850 mm$
(IV) Number of sub-divisions having at least 1000 m rainfall = 2 + 3 + 1 + 1 = 7.
Hence, 7 sub-divisions have good rainfall
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$($ Take $\pi=22 / 7)$
(a) $75 m^2$$\quad$ (b) $78.57 m^2$$\quad$ (c) $87.47 m^2$$\quad$(d) $25.8 m^2$
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(a) $\pi r^2 h$$\quad$ (b) $\pi r l$$\quad$ (c) $\pi r(i+r)$$\quad$ (d) $2 \pi r$
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(a) $2(x+5) km$ $\qquad$ (b) $(x-5) km$
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(a) 20 $\qquad$ (b) 15 $\qquad$ (c) 25 $\qquad$ (d) 10
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(a) 25 $\qquad$ (b) 20 $\qquad$ (c) 30 $\qquad$ (d) 15
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(a) $2(x+5) km$ $\qquad$ (b) $(x-5) km$
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