MCQ
Inert pair effect is predominant in
- A$Si$
- ✓$Pb$
- C$Ge$
- D$Sn$
This is most stated in Groups 13,14 and 15
A possible given explanation is that due to presence of f-subshell electrons are to diffused, due to the shape of the forbitals, to effectively shield the s electrons from the pull of the nucleus.
A good example would be the elements of Group $13 .$ Aluminium in +1 state is unknown, and the stability of +1 oxidation state increases as we go down the group.
Thallium is most stable in +1 oxidation state, and compounds of Thallium in +3 oxidation state are known to be very strong oxidising agents, and have a tendency to reduce quickly to +1 state.
Hence option B is correct.
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$(A)$ ${SO}_{3}$ $(B)$ ${NO}_{3}^{-}$ $(C)$ ${PCl}_{3}$ $(D)$ ${CO}_{3}^{2-}$