Question
Insert three numbers between 1 and 256 so that the resulting sequence is a G.P.

Answer

Suppose G1, G2, G3 be three numbers between 1 and 256 such that 1, G1,G2, G3, 256 is a G.P.
Thus, 256 = r4 giving r = $\pm$4 (Taking real roots only)
For r = 4, we have G1 = ar = 4, G2 = ar2 = 16, G3 = ar3 = 64
Similarly, for r = - 4, numbers are - 4,16 and - 64
Therefore,we can insert 4, 16, 64 between 1 and 256 so that the resulting sequences are in G.P.

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