Instantaneous displacement current 1A in the space between the parallel plates of 1 capacitor can be established by changing the potential difference at the rate of:

Instantaneous displacement current 1A in the space between the pa…

MCQ

Instantaneous displacement current $1A$ in the space between the parallel plates of $1\mu\text{F}$ capacitor can be established by changing the potential difference at the rate of:

A
$\frac{0.1\text{V}}{\text{s}}$
B
$\frac{1\text{V}}{\text{s}}$
✓
$\frac{10^6\text{V}}{\text{s}}$
D
$\frac{10^{-6}\text{V}}{\text{s}}$

✓

Answer

Correct option: C.

$\frac{10^6\text{V}}{\text{s}}$

In a capacitor of capacitance $C,$
$\text{V}=\frac{\text{q}}{\text{C}}$
$\Rightarrow\frac{\text{dV}}{\text{dt}}=\frac{\text{i}}{\text{C}}=\frac{1\text{A}}{1\mu\text{F}}=\frac{10^6\text{V}}{\text{s}}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Electromagnetic Waves→Electromagnetic Waves — all question types→Physics STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

The two bulbs as in the above question are connected in series to a $200\, volt$ line. Then

→

A parallel plate capacitor has an electric field of ${10^5}\,V/m$ between the plates. If the charge on the capacitor plate is $1\,\mu \,C$, the force on each capacitor plate is......$N$

→

In the previous question, if the current is $i$ and the magnetic field at $D$ has magnitude $B$,

→

Match List $I$ with List $II$

LIST $I$	LIST $II$
$A$ Planck's constant $( h )$	$I$ $\left[ M ^1 L ^2 T ^{-2}\right]$
$B$ Stopping potential $( Vs )$	$II$ $\left[ M ^1 L ^1 T ^{-1}\right]$
$C$ Work function $(\phi)$	$III$ $\left[ M ^1 L ^2 T ^{-1}\right]$
$D$ Momentum $( p )$	$IV$ $\left[ M ^1 L ^2 T ^{-3} A ^{-1}\right]$