MCQ
$\int_{-1}^1 \frac{|x-2|}{x-2} d x, x \neq 2$ is equal to
  • A
    1
  • B
    -1
  • C
    2
  • D
    -2

Answer

Let $I=\int_{-1}^1 \frac{|x-2|}{x-2} d x$
$
=\int_{-1}^1 \frac{-(x-2)}{x-2} d x=\int_{-1}^1-1 \cdot d x=[-x]_{-1}^1=-[1-(-1)]=-2
$

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