Question
$\int_{ - 1}^1 {\log \frac{{2 - x}}{{2 + x}}\,dx} = $
$ \Rightarrow f( - x) = \log {\left( {\frac{{2 - x}}{{2 + x}}} \right)^{ - 1}} $
$= - \log \left( {\frac{{2 - x}}{{2 + x}}} \right) = - f(x)$
$\therefore $ $\int_{ - 1}^1 {\log \left( {\frac{{2 - x}}{{2 + x}}} \right)\,\,dx = 0} $.
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