MCQ
$\int_{ - 1}^1 {{x^{17}}{{\cos }^4}x} \,dx = $
- A$ - 2$
- B$ - 1$
- ✓$0$
- D$2$
$f( - x) = {( - x)^{17}}{\left\{ {\cos ( - x)} \right\}^4} = - f(x)$
Therefore, $\int_{ - 1}^1 {{x^{17}}{{\cos }^4}x\,dx = 0} $.
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If $f$ is continuous, then which of the following hold$(s)$ for all $n$ ?
$(A)$ $a_{n-1}-b_{n-1}=0$ $(B)$ $a_n-b_n=1$ $(C)$ $a_n-b_{n+1}=1$ $(D)$ $a_{n-1}-b_n=-1$