Question
$\int_{ - 1}^1 {x\,|x|\,} dx = $
तब $f( - x) = - x| - x| = - x|x| = - f(x)$
इसलिए $\int_{ - 1}^1 {x|x|dx = 0} $, (निश्चित समाकल के प्रगुण से).
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