MCQ
$\int_{ - 1}^1 {x\,|x|\,} dx = $
- A$1$
- ✓$0$
- C$2$
- D$ - 2$
Then $f( - x) = - x| - x| = - x|x| = - f(x)$
Therefore $\int_{ - 1}^1 {x|x|dx = 0} $, (By the property of definite integral).
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