Question
$\int_{\, - 1}^{\,2} {|x|\,dx} = $
$ = - \left[ {\frac{{{x^2}}}{2}} \right]_{ - 1}^0 + \left[ {\frac{{{x^2}}}{2}} \right]_0^2$
$ = - \left[ {0 - \frac{1}{2}} \right] + [2]$
$ = 2 + \frac{1}{2} = \frac{5}{2}$.
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