MCQ
$\int\frac{-1}{\text{y}^2}\text{dy}$ is:
  • $\frac{1}{\text{y}}$
  • B
    1 - y
  • C
    y
  • D
    1 + y

Answer

Correct option: A.
$\frac{1}{\text{y}}$
$\int\frac{-1}{{\text{y}}^2}\text{dy}$

$=-\int\text{y}^{-2}\text{dy}$

$=\text{y}^{-1}=\frac{1}{\text{y}}$

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