1+x+x+x^2 x+1+x d x= - Vidyadip

MCQ

$\int \frac{1+x+\sqrt{x+x^2}}{\sqrt{x}+\sqrt{1+x}} \cdot d x=$

A
$\frac{1}{2} \sqrt{x+1}+c$
✓
$\frac{2}{3}(x+1)^{\frac{3}{2}}+c$
C
$\sqrt{x+1}+c$
D
$2(x+1)^{\frac{3}{2}}+c$

✓

Answer

Correct option: B.

$\frac{2}{3}(x+1)^{\frac{3}{2}}+c$

$\frac{2}{3}(x+1)^{\frac{3}{2}}+c$

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