Question
$\int_{\, - 2}^{\,2} {|x|\,dx = } $

Answer

d
(d) $I = \int_{ - 2}^2 {|x|dx} $$ = - \int_{ - 2}^0 {x\,dx + \int_0^2 {x\,dx} } $

$ = - \left[ {\frac{{{x^2}}}{2}} \right]_{ - 2}^0 + \left[ {\frac{{{x^2}}}{2}} \right]_0^2$ 

$ = - ( - 2) + (2) = 4$.

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