MCQ
$\int_{-2}^2\left|1-x^2\right| d x=$
  • A
    2
  • 4
  • C
    6
  • D
    8

Answer

Correct option: B.
4
(B)
$\int_{-2}^2\left|1-x^2\right| d x$
$\begin{array}{l}=\int_{-2}^{-1}\left|1-x^2\right| d x+\int_{-1}^1\left|1-x^2\right| d x+\int_1^2\left|1-x^2\right| d x \\ =-\int_{-2}^{-1}\left(1-x^2\right) d x+\int_{-1}^1\left(1-x^2\right) d x-\int_1^2\left(1-x^2\right) d x \\ =-\left[x-\frac{x^3}{3}\right]_{-2}^{-1}+\left[x-\frac{x^3}{3}\right]_{-1}^1-\left[x-\frac{x^3}{3}\right]_1^2 \\ =\frac{4}{3}+\frac{4}{3}+\frac{4}{3}=4\end{array}$

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