_ - 3 ^3 x^2 2x x^2 + 1 ,dx = - Vidyadip

Question

$\int_{ - 3}^3 {\frac{{{x^2}\sin 2x}}{{{x^2} + 1}}\,dx = } $

✓

Answer

a
(a) Obviously the function $\frac{{{x^2}\sin 2x}}{{{x^2} + 1}}$ is odd,

so $\int_{ - 3}^3 {\frac{{{x^2}\sin 2x}}{{{x^2} + 1}}\,} dx = 0$.

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