Question
$
\int_{-4}^{-1} \frac{1}{x} d x
$

Answer

$
\begin{aligned}
& \int_{-4}^{-1} \frac{1}{x} d x=[\log |x|]_{-4}^{-1} \\
= & \log |-1|-\log |-4| \\
= & \log 1-\log 4 \\
= & -\log 4 . \quad \ldots[\because \log 1=0]
\end{aligned}
$

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