5 (x^6+1 ) x^2+1 d x=x^4+ x^3+5 x+c - Vidyadip

Question

$\int \frac{5\left(x^6+1\right)}{x^2+1} d x=x^4+\ldots x^3+5 x+c$

✓

Answer

$-\frac{5}{3}$
Hint:
$
x^6+1=\left(x^2+1\right)\left(x^4-x^2+1\right)
$

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