MCQ
$\int \frac{\cos 2 x}{(\sin x+\cos x)^2} d x=$
- A$\frac{-1}{\sin x+\cos x}+c$
- ✓$\log |\sin x+\cos x|+c$
- C$\log |\sin x-\cos x|+c$
- D$\frac{1}{(\sin x+\cos x)^2}+ C$
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$\overrightarrow{\mathrm{a}} \times\{(\overrightarrow{\mathrm{r}}-\overrightarrow{\mathrm{b}}) \times \overrightarrow{\mathrm{a}}\}+\overrightarrow{\mathrm{b}} \times\{(\overrightarrow{\mathrm{r}}-\overrightarrow{\mathrm{c}}) \times \overrightarrow{\mathrm{b}}\}+\overrightarrow{\mathrm{c}} \times\{(\overrightarrow{\mathrm{r}}-\overrightarrow{\mathrm{a}}) \times \overrightarrow{\mathrm{c}}\}=\overrightarrow{0}$
નું સમાધાન કરે છે તો $\overrightarrow{\mathrm{r}}$ મેળવો.