MCQ
$\int \frac{1-\cos x}{1+\cos x} d x=$ __________  + C .
  • $2 \tan \frac{x}{2}-x$
  • B
    $2 \tan \frac{x}{2}+x$
  • C
    $-2 \tan \frac{x}{2}-x$
  • D
    $-\tan \frac{x}{2}-x$

Answer

Correct option: A.
$2 \tan \frac{x}{2}-x$
A

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The maximum value of Z = 4x + 2y Subjected to the constraints $2\text{x}+3\text{y}\leq18,\text{x}+\text{y}\geq10,\text{x},\text{y}\geq0$ is:
  1. 36
  2. 40
  3. 20
  4. none of these
If $A$ is a square matrix of order 3 , such that $A(\operatorname{adj} A)=$ $10 I$, then $\mid$ adj $A \mid$ is equal to
$\int_{}^{} {\frac{{x + 1}}{{\sqrt {1 + {x^2}} }}dx} = $
$\int_{0}^{1}\frac{\text{x}}{1+\text{x}}\text{dx}=$
  1. $1-\log2$
  2. $2$
  3. $1+\log 2$
  4. $\log2$
If ${a_1},{a_2},{a_3}.....{a_n}....$ are in $G.P.$ then the value of the determinant $\left| {\,\begin{array}{*{20}{c}}{\log {a_n}}&{\log {a_{n + 1}}}&{\log {a_{n + 2}}}\\{\log {a_{n + 3}}}&{\log {a_{n + 4}}}&{\log {a_{n + 5}}}\\{\log {a_{n + 6}}}&{\log {a_{n + 7}}}&{\log {a_{n + 8}}}\end{array}\,} \right|$ is
If the function $f(x)=\left(\frac{1}{x}\right)^{2 x} ; x>0$ attains the maximum value at $\mathrm{x}=\frac{1}{\mathrm{e}}$ then :
If the function f(x) = x3 - 9kx2 + 27x + 30 is increasing on R, then:
  1. $-1\leq\text{k}\leq1$
  2. k < -1 or k > 1
  3. 0 < k < 1
  4. -1 < k < 0
The degree of the differential equation $\left(\frac{d s}{d t}\right)^4+3 s \frac{d^2 s}{d t^2}=0$ is :
Let $f (x)$ be diffrentiable at $x = h$ then $\mathop {\lim }\limits_{x \to h} \,\frac{{(x + h)\,f(x)\, - 2h\,f(h)}}{{x - h}}$ is equal to
If the function $f\left( x \right) = \left\{ {\begin{array}{*{20}{c}}
  {\frac{{\sqrt {2  + \cos \,x} - 1}}{{\left( {\pi  - {x^2}} \right)}},}&{x \ne \pi } \\ 
  {k\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,,}&{x = \pi } 
\end{array}} \right.$ is continuous at $x\, =\pi $ , then $k$ equals