Question
$\int \frac{10 x^{9}+10^{x} \log _{e} 10 d x}{x^{10}+10^{x}}$,  equals

Answer

Let x10 + 10x = t
$\Rightarrow$ (10x9 + 10x loge10)dx = dt
$\Rightarrow \int \frac{10 x^{9}+10^{x} \log _{e} 10}{x^{10}+10^{x}} d x=\int \frac{d t}{t}$ 
= log t + C
= log(x10 + 10x) + C

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