Question
$\int\frac{2\text{x}+3}{(\text{x}-1)^2}\text{dx}$

Answer

$\int\bigg(\frac{2\text{x}+3}{(\text{x}-1)^2}\bigg)\text{dx}$
$=\int\bigg[\frac{2\text{x}-2+2+3}{(\text{x}-1)^2}\bigg]\text{dx}$
$=\int\bigg[\frac{2(\text{x}-1)+5}{(\text{x}-1)^2}\bigg]\text{dx}$
$=2\int\frac{\text{dx}}{(\text{x}-1)}+5\int(\text{x}-1)^{-2}\text{dx}$
$=2\text{ln}|\text{x}-1|+5\bigg[\frac{(\text{x}-1)^{-2+1}}{-2+1}\bigg]+\text{C}$
$=2\text{ln}|\text{x}-1|-\frac{5}{\text{x}-1}+\text{c}$

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