MCQ
$\int_{}^{} {\frac{{dx}}{{(x - {x^2})}} = } $
- ✓$\log x - \log (1 - x) + c$
- B$\log (1 - {x^2}) + c$
- C$ - \log x + \log (1 - x) + c$
- D$\log (x - {x^2}) + c$
✓
Answer
Correct option: A.
$\log x - \log (1 - x) + c$
a
(a)$\int_{}^{} {\frac{{dx}}{{(x - {x^2})}} = \int_{}^{} {\left( {\frac{1}{x} + \frac{1}{{1 - x}}} \right)} {\rm{ }}dx = \log x - \log (1 - x) + c} $.
(a)$\int_{}^{} {\frac{{dx}}{{(x - {x^2})}} = \int_{}^{} {\left( {\frac{1}{x} + \frac{1}{{1 - x}}} \right)} {\rm{ }}dx = \log x - \log (1 - x) + c} $.
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