MCQ
$\int_{}^{} {\frac{{dx}}{{{x^2} + 2x + 2}} = } $
- A${\sin ^{ - 1}}(x + 1) + c$
- B${\sinh ^{ - 1}}(x + 1) + c$
- C${\tanh ^{ - 1}}(x + 1) + c$
- ✓${\tan ^{ - 1}}(x + 1) + c$
✓
Answer
Correct option: D.
${\tan ^{ - 1}}(x + 1) + c$
d
(d)$\int_{}^{} {\frac{{dx}}{{{x^2} + 2x + 2}} = \int_{}^{} {\frac{{dx}}{{{{(x + 1)}^2} + 1}} = {{\tan }^{ - 1}}(x + 1) + c} } $.
(d)$\int_{}^{} {\frac{{dx}}{{{x^2} + 2x + 2}} = \int_{}^{} {\frac{{dx}}{{{{(x + 1)}^2} + 1}} = {{\tan }^{ - 1}}(x + 1) + c} } $.
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