_ - 4 ^ 4 dx 1+ 2x dx is equal to: 1. 1 2. 2 3. 3 4. 4 - Vidyadip

Question

$\int_{\frac{-\pi}{4}}^{\frac{\pi}{4}}\frac{\text{dx}}{1+\cos2\text{x}}\text{dx}$ is equal to:

1
2
3
4

✓

Answer

1

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The area bounded by the curves $x + 2y^2 = 0$ and $x + 3y^2 = 1$ is$:$

The line x = 1, y = 2 is:

Parallel to x-axis
Parallel to y-axis
Parallel to z-axis
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The direction ratios of the line x - y + z - 5 = 0 = x - 3y - 6 are proportional to:

$3,1,-2$
$2,-4,1$
$\frac{3}{\sqrt{14}},\frac{1}{\sqrt{14}},\frac{-2}{\sqrt{14}}$
$\frac{2}{\sqrt{41}},\frac{-4}{\sqrt{41}},\frac{1}{\sqrt{41}}$

If $\alpha=\tan^{-1}\Big(\frac{\sqrt3\text{x}}{2\text{y}-\text{x}}\Big),\beta=\tan^{-1}\Big(\frac{2\text{x}-\text{y}}{\sqrt3\text{y}}\Big),$ then $\alpha-\beta=$

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$\frac{\pi}{2}$
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The direction coisines of the y-axis are:

If $\alpha,\beta,\gamma$ are the angle which a half ray makes with the positive directions of the axis then $\sin^2\alpha + \sin^2\beta + \sin^2\gamma =$

1
2
0
-1

The plane $2\text{x}-(1-\lambda)\text{y}+3\lambda\text{z}=0$ passes through the intersection of the planes:

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In the interval (1, 2), function f(x) = 2|x - 1| + 3|x - 2| is:

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Decreasing.
Constant.
None of these.

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$\begin{bmatrix}2&2&-4\\2&3&4\\-4&4&2\end{bmatrix}$
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$\begin{bmatrix}4&4&-8\\4&6&8\\-8&8&4\end{bmatrix}$
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Let f : R → R be a function defined by $\text{f(x)}=\frac{\text{e}^{|\text{x}|}-\text{e}^{-\text{x}}}{\text{e}^{\text{x}}+\text{e}^{-\text{x}}}.$ Then,

f is a bijection.
f is an injection only.
f is surjection on only.
f is neither an injection nor a surjection.