MCQ
$\int_{}^{} {\frac{{{\rm{cosec}}\theta - \cot \theta }}{{{\rm{cosec}}\theta + \cot \theta }}} \;d\theta = $
  • $2{\rm{cosec}}\theta - 2\cot \theta - \theta + c$
  • B
    $2\,{\rm{cosec}}\theta - 2\cot \theta + \theta + c$
  • C
    $2\,{\rm{cosec}}\theta + 2\cot \theta - \theta + c$
  • D
    None of these

Answer

Correct option: A.
$2{\rm{cosec}}\theta - 2\cot \theta - \theta + c$
a
(a)$\int_{}^{} {\frac{{{\rm{cosec}}\theta - \cot \theta }}{{{\rm{cosec}}\theta + \cot \theta }}\,d\theta } = \int_{}^{} {{{({\rm{cosec}}\theta - \cot \theta )}^2}d\theta } $
$ = \int_{}^{} {{\rm{cose}}{{\rm{c}}^2}\theta \,d\theta } + \int_{}^{} {{{\cot }^2}\theta \,d\theta } - 2\int_{}^{} {{\rm{cosec}}\theta \cot \theta \,d\theta } $
$ = \int_{}^{} {(2{\rm{cose}}{{\rm{c}}^2}\theta - 1)\,d\theta } - 2\int_{}^{} {{\rm{cosec}}\theta \cot \theta \,d\theta } $
$ = 2{\rm{cosec}}\theta - 2\cot \theta - \theta + c.$

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