x x- x d x equals - Vidyadip

MCQ

\[\int \frac{\sec x}{\sec x-\tan x} d x \text { equals }\]

A
$\sec x-\tan x+c$
B
$\sec x+\tan x+c$
C
$\tan x-\sec x+c$
D
$-(\sec x+\tan x)+c$

✓

Answer

$\begin{array}{l}\text {Let } I=\int \frac{\sec x}{\sec x-\tan x} d x \\ =\int \frac{\sec x(\sec x+\tan x)}{(\sec x-\tan x)(\sec x+\tan x)} d x=\int\left(\frac{\sec ^2 x+\sec x \tan x}{\sec ^2 x-\tan ^2 x}\right) d x \\ =\int \sec ^2 x d x+\int \sec x \tan x d x \quad\left[\because \sec ^2 x-\tan ^2 x=1\right] \\ =\tan x+\sec x+c\end{array}$

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