Question
$\int_{}^{} {\frac{{\sqrt {\tan x} }}{{\sin x\cos x}}} \;dx = $
$ = \int_{}^{} {\frac{{\sin x\sec x}}{{\sqrt {\tan x} \sin x\cos x}}\,dx} = \int_{}^{} {\frac{{{{\sec }^2}x}}{{\sqrt {\tan x} }}\,dx} $
$t = \tan x $ रखने पर $dt = {\sec ^2}x\,dx,$
$\int_{}^{} {\frac{1}{{\sqrt t }}\,dt} = 2{t^{1/2}} + c = 2\sqrt {\tan x} + c$.
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$(A)$ $1 < e < \sqrt{2}$
$(B)$ $\sqrt{2} < e < 2$
$(C)$ $\Delta=a^4$
$(D)$ $\Delta=b^4$