MCQ
$\int \frac{x^2+1}{x^4-x^2+1} d x=?$
- A$\tan ^{-1}\left(\frac{x^2+1}{2}\right)+ c$
- ✓$\tan ^{-1}\left(\frac{x^2-1}{x}\right)+c$
- C$\tan^{-1} (x^2) + c$
- D$\tan^{-1} (2x^2- 1) + c$
✓
Answer
Correct option: B.
$\tan ^{-1}\left(\frac{x^2-1}{x}\right)+c$
$\tan ^{-1}\left(\frac{x^2-1}{x}\right)+c$
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