MCQ
$\int_{}^{} {{e^{{{\cos }^2}x}}\sin 2x\;dx = } $
- A${e^{{{\cos }^2}x}} + c$
- ✓$ - {e^{{{\cos }^2}x}} + c$
- C$1/2{e^{{{\cos }^2}x}} + c$
- DNone of these
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The solution of the differential equation $\frac{\text{dy}}{\text{dx}}+\frac{2\text{xy}}{1+\text{x}^2}=\frac{1}{(1+\text{x}^2)^2}$ is:
$\text{y}(1+\text{x}^2)=\text{C}+\tan^{-1}\text{x}$
$\frac{\text{y}}{1+\text{x}^2}=\text{C}+\tan^{-1}\text{x}$
$\text{y}\log(1+\text{x}^2)=\text{C}+\tan^{-1}\text{x}$
$\text{y}(1+\text{x}^2)=\text{C}+\sin^{-1}\text{x}$