MCQ
$\int {{{\left( {\frac{{x + 2}}{{x + 4}}} \right)}^2}{e^x}\,\,dx} $ is equal to
- ✓${e^x}\left( {\frac{x}{{x + 4}}} \right) + c$
- B${e^x}\left( {\frac{{x + 2}}{{x + 4}}} \right) + c$
- C${e^x}\left( {\frac{{x - 2}}{{x + 4}}} \right) + c$
- D$\left( {\frac{{2x{e^x}}}{{x + 4}}} \right) + c$