MCQ
$
\int \frac{\left(x^3+3 x^2+3 x+1\right)}{(x+1)^5} d x=
$
\int \frac{\left(x^3+3 x^2+3 x+1\right)}{(x+1)^5} d x=
$
- ✓$\frac{-1}{x+1}+ c$
- B$\left(\frac{-1}{x+1}\right)^5+ c$
- C$\log (x+1)+c$
- D$5 \log (x+5)+c$
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