MCQ
$\int \frac{\log (3 x)}{x \log (9 x)} \cdot d x=$
- A$log(3x) – log(9x) + c$
- B$log(x) – (log 3) . log(log 9x) + c$
- C$\log 9-(\log x) \cdot \log (\log 3 x)+c$
- ✓$\log (x)+\log (3) \cdot \log (\log 9 x)+c$
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