Question
$\int_{-\pi / 4}^{\pi / 4} \sec ^2 x d x$ is equal to
✓
Answer
$\text {Let } I=\int_{-\pi / 4}^{\pi / 4} \sec ^2 x d x=[\tan x]_{-\pi / 4}^{\pi / 4}$
$=\tan \frac{\pi}{4}-\tan \left(-\frac{\pi}{4}\right)=1+1=2$
$=\tan \frac{\pi}{4}-\tan \left(-\frac{\pi}{4}\right)=1+1=2$
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