Download App

Integrals — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsIntegrals1 Mark
MCQ
$\int_{-\pi / 4}^{\pi / 4} \sec ^2 x d x$ is equal to
  • A
    -1
  • B
    $0$
  • C
    1
  • D
    2
✓

Answer

$\begin{array}{l}\text {Let } I=\int_{-\pi / 4}^{\pi / 4} \sec ^2 x d x=[\tan x]_{-\pi / 4}^{\pi / 4} \\ =\tan \frac{\pi}{4}-\tan \left(-\frac{\pi}{4}\right)=1+1=2\end{array}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Integrals→Integrals — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

If four distinct points with position vectors $\vec{a}, \vec{b}, \vec{c}$ and $\vec{d}$ are coplanar; then $[\vec{a} \vec{b} \vec{c}]$ is equal to
→
Let $\vec a\, = \,\hat i\, + \,2\hat j\, + 4\hat k\,,\,\vec b\, = \,\hat i\, + \,\lambda \hat j\, + 4\hat k$ and $\vec c\, = \,2\hat i\, + \,4\hat j\, + ({\lambda ^2} - 1)\hat k$ be coplanar vectors. Then the non -zero vector $\vec a\times \vec c$ is
→
If ${\tan ^{ - 1}}2x + {\tan ^{ - 1}}3x = \frac{\pi }{4}$, then $x =$
→
Let $y=y(x)$ be the solution of the differential equation $x^3 d y+(x y-1) d x=0, x>0$, $y\left(\frac{1}{2}\right)=3-e$. Then $y(1)$ is equal to
→
If $f\left( x \right) = {e^{{{\left( {x + 1} \right)}^n}}};\left( {n \in N} \right)$ then value of $'n'$ for which $f''\left( 1 \right) = 67\left( {{2^n}{e^{2n}}} \right)$ is
→
Let the solution curve $y = y ( x )$ of the differential equation,

$\left[\frac{x}{\sqrt{x^{2}-y^{2}}}+e^{\frac{y}{x}}\right] x \frac{d y}{d x}=x+\left[\frac{x}{\sqrt{x^{2}-y^{2}}}+e^{\frac{y}{x}}\right] y$

pass through the points $(1,0)$ and $(2 \alpha, \alpha), \alpha>0$.

Then $\alpha$ is equal to

→
Distance between the two planes $2 x+3 y+4 z=4$ and $4 x+6 y+8 z=12$ is_________ units.
→
Integration of function $\frac{x}{e^{x^2}}$ with respect to $x$ is equal to :
→
$\int \frac{d x}{1-e^x}$ is equal to :
→
Let $f : R \to R$, be defined as $f(x) = e^{x^2} + cosx$ ,then $f$ is -
→