Question
$\int \frac{\sin 4 x}{\cos 2 x} d x$

Answer

$\int \frac{\sin 4 x}{\cos 2 x} d x$
$=\int \frac{\sin 2(2 x)}{\cos 2 x} d x$
$=\int \frac{2 \sin 2 x \cos 2 x}{\cos 2 x} d x$
$=2 \int \sin 2 x d x$
$=2 \cdot \frac{(-\cos 2 x)}{2}+c$
$=-\cos 2 x+c$

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