MCQ
$\int {{{\sin }^{\frac{{ - 1}}{2}}}x{{\cos }^{\frac{{ - 7}}{2}}}xdx = } $
  • A
    $\tan^{\frac{1}{2}}x + \tan^{\frac{5}{2}}x + C$
  • B
    $2 \tan^{\frac{1}{2}}x + \frac{1}{5} \tan^{\frac{5}{2}}x + C$
  • $2 \tan^{\frac{1}{2}}x + \frac{2}{5} \tan^{\frac{5}{2}}x + C$
  • D
    None

Answer

Correct option: C.
$2 \tan^{\frac{1}{2}}x + \frac{2}{5} \tan^{\frac{5}{2}}x + C$
c

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If $f (x) = e^{-x} + 2 e^{-2x} + 3 e^{- 3x} +...... + \infty$ , then $\int\limits_{\ln 2}^{\ln 3} {f(x)\,dx}  =$
Total number of divisors of $480$, that are of the form $4n + 2, n \geq 0$, is equal to :-
Let $(\alpha, \beta)$ be the centroid of the triangle formed by the lines $15 x-y=82,6 x-5 y=-4$ and $9 x+4 y=17$. Then $\alpha+2 \beta$ and $2 \alpha-\beta$ are the roots of the equation $...........$.
Let $S$ be the sum of the first $9$ terms of the series: $\{x+k a\}+\left\{x^{2}+(k+2) a\right\}+\left\{x^{3}+(k+4) a\right\}+$ $\left\{x^{4}+(k+6) a\right\}+\ldots \ldots$ where $a \neq 0$ and $x \neq 1 .$ If $S =\frac{ x ^{10}- x +45 a ( x -1)}{ x -1},$ then $k$ is equal to
Area bounded by curve $y = {x^3},$ $x - $ axis and ordinates $x = 1$ and $x = 4,$ is
The value of $\sqrt {[12\sqrt 5 + 2\sqrt {(55)} ]} $ is
Suppose $a_{1}, a_{2}, \ldots, a_{ n }, \ldots$ be an arithmetic progression of natural numbers. If the ratio of the sum of the first five terms of the sum of first nine terms of the progression is $5: 17$ and $110< a_{15} < 120$ , then the sum of the first ten terms of the progression is equal to -
If mean = ($3$ median -mode) $k$, then the value of $k$ is
If the normal at the point $P(\theta )$ to the ellipse $\frac{{{x^2}}}{{14}} + \frac{{{y^2}}}{5} = 1$ intersects it again at the point $Q(2\theta )$, then $\cos \theta $ is equal to
The option$(s)$ with the values of $a$ and $L$ that satisfy the following equation is(are) $\frac{\int_0^{4 \pi} e^t\left(\sin ^6 a t+\cos ^4 a t\right) d t}{\int_0^\pi e^t\left(\sin ^6 a t+\cos ^4 a t\right) d t}=L ?$

$(A)$ $a=2, L=\frac{e^{4 \pi}-1}{e^\pi-1}$ $(B)$ $a=2, L=\frac{e^{4 \pi}+1}{e^\pi+1}$

$(C)$ $a=4, L=\frac{e^{4 \pi}-1}{e^\pi-1}$ $(D)$ $a=4, L=\frac{e^{4 \pi}+1}{e^\pi+1}$