b (b) $\sqrt x = t $ रखने पर $ \Rightarrow \frac{1}{{2\sqrt x }}\,dx = dt \Rightarrow dx = 2t\,dt,$ तब
$\int_{}^{} {\sin \sqrt x \,dx} = 2\int_{}^{} {t\sin t\,dt} = 2( - t\cos t + \sin t) + c$
$ = 2(\sin \sqrt x - \sqrt x \cos \sqrt x ) + c.$
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