_ ^ 1 - 2x ; dx = ........, ; ;x (0, ; /4) - Vidyadip

MCQ

$\int_{}^{} {\sqrt {1 - \sin 2x} \;} dx = ........,\;\;x \in (0,\;\pi /4)$

A
$ - \sin x + \cos x$
B
$\sin x - \cos x$
C
$\tan x + \sec x$
✓
$\sin x + \cos x$

✓

Answer

Correct option: D.

$\sin x + \cos x$

d
(d) $\int_{}^{} {\sqrt {1 - \sin 2x} } \,\,dx$
$ = \int_{}^{} {(\cos x - \sin x)dx = \sin x + \cos x + c.} $

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