Question
$
\int \sqrt{1+x^2} \cdot x d x=\frac{1}{3}\left(1+x^2\right)^{\frac{3}{2}}+ c
$
\int \sqrt{1+x^2} \cdot x d x=\frac{1}{3}\left(1+x^2\right)^{\frac{3}{2}}+ c
$
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